A number puzzle (Middle School Math Challenge) Help?
Can anyone solve this:

Arrange the nine digits ( 1,2,3,4,5,6,7,8,9 ) into 3 groups. Make one group of 2 digits, one group of 3 digits, and one group of four digits, so that when you multiply the first group and the second group, you get the third group of four ( each digits used once)

Example: 39(186)=7,254

There are 6 different combinations.

10 points!
Can u find them all?

42*138=5796
12*483=5796
18*297=5346
48*159=7632
27*198=5346
28*157=4396

Plus the one you already gave: 39*186=7254

One Response

1. Sean L Says:
   November 22nd, 2009 at 3:17 am

   42*138=5796
   12*483=5796
   18*297=5346
   48*159=7632
   27*198=5346
   28*157=4396

   Plus the one you already gave: 39*186=7254
   References :
   http://members.tripod.com/~aniketd/maths.html

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